Find a quadratic polynomial whose sum and product of the zeroes are 4 and 1 respectively. Also find the zeroes?
Answers
αβ=1
=k(x²-(α+β)x+αβ)
=k(x²-4x+1)
polynomial is x²-4x+1
k=1
Given,
- Sum of the zeroes = 4
- Product of the zeroes = 1
To find,
We have to find the
- quadratic polynomial
- the zeroes of the polynomial
Solution,
We can simply find the quadratic polynomial by using the following formula:
x² -(sum of the zeroes)x + (product of the zeroes) (*)
Sum of the zeroes = 4
Product of the zeroes = 1
Using (*), we get
x² - 4x + 1
which is the required quadratic polynomial.
Now, for the zeroes of the polynomial, let us factorize the polynomial by using the quadratic formula:
x = -b±√D/2a (**)
D = b²-4ac
where b = -4, a = 1, c = 1
D = (-4)²-4(1)(1)
D = 16-4
D = 12
Using (**), we get
x = -(-4) ± √12/2(1)
x = 4 ± 2√3/2
x = 4+2√3/2, x = 4-2√3/2
Hence, the quadratic polynomial whose sum and product of the zeroes are 4 and 1 respectively is x² - 4x + 1, and the zeroes of the polynomial are 4+2√3/2 and 4-2√3/2.