find a quadratic polynomial whose sum and product of zeroes are -8/3 , 4/3
Answers
Answered by
75
Hiii friend,
Let alpha and beta are the zeroes of the polynomial.
Sum of zeroes = (Alpha + Beta) = -8/3
And,
Product of zeroes = (Alpha × Beta) = 4/3
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X + Alpha × Beta
=> X²-(-8/3) X + 4/3
=> X²+8X/3 + 4/3
=> 3X²+8X+4/3 = 0
=> 3X²+8X+4 = 0 × 3
=> 3X²+8X+4 = 0
Hence,
The Quadratic polynomial is 3X²+8X+4
HOPE IT WILL HELP YOU....... :-)
Let alpha and beta are the zeroes of the polynomial.
Sum of zeroes = (Alpha + Beta) = -8/3
And,
Product of zeroes = (Alpha × Beta) = 4/3
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X + Alpha × Beta
=> X²-(-8/3) X + 4/3
=> X²+8X/3 + 4/3
=> 3X²+8X+4/3 = 0
=> 3X²+8X+4 = 0 × 3
=> 3X²+8X+4 = 0
Hence,
The Quadratic polynomial is 3X²+8X+4
HOPE IT WILL HELP YOU....... :-)
sakshi471:
Thank u soo much Saniya
Answered by
19
let the zeros be A and B.
given that A+B= -8/3 and
AB= 4/3.
then the given polynomial will be
x2 -( A+B )x + (AB)
=> x2 + 8/3x + 4/3.
here x2 is
hope it helps. if yes mark it as Brainliest.
given that A+B= -8/3 and
AB= 4/3.
then the given polynomial will be
x2 -( A+B )x + (AB)
=> x2 + 8/3x + 4/3.
here x2 is
hope it helps. if yes mark it as Brainliest.
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