Find a quadratic polynomial whose sum and product of zeroes are √2 and 3 respectively.
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x+y=underroot 2--eq1
And x*y=3
x=3/y
Now put value in eq 1
3/y+y=√2
3+y2÷y =√2
So 3+y2=√2y
Hence we get an quadratic eq
y^2-√2y+3=0
Now solve it and get value of y and then put the value of y in eq 1 from there you get value of x
And x*y=3
x=3/y
Now put value in eq 1
3/y+y=√2
3+y2÷y =√2
So 3+y2=√2y
Hence we get an quadratic eq
y^2-√2y+3=0
Now solve it and get value of y and then put the value of y in eq 1 from there you get value of x
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