Find a quadratic polynomial whose sum and zores are4,5 respectively
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Answered by
0
Step-by-step explanation:
Let the required polynomial be p ( x ) .
Its zeros are 4 and 5 .
Let , a = 4 and , b = 5 .
Since , a polynomial with zeros a and b is given by
k { x ^2 - ( a + b ) x + ab } , where k is a constant then the required polynomial
p ( x ) is k { x ^2 - ( 4 + 5 ) x + 4×5 }
= k { x^2 - 9 x + 20 }
Let k = 1 as constant .
The required polynomial is x^2 - 9x + 20
Answered by
5
Let,
- Sum of the zeroes : α + ß = 4
- Product of the zeroes : αß = 5
Form of quadratic polynomial is
↪ x² - (α + ß)x + αß = 0
- Substitute the zeroes
➡ x² - (4)x + 5 = 0
➡ x² - 4x + 5 = 0
Hence, it is solved...
Step-by-step explanation:
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