Question

Find a quadratic polynomial whose zero are -9 and -1/9

Answer 1

Hey friend..!! here's your answer
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Sum of zeroes = -9
Product of zeroes = -1/9

Formula of Quardatic polynomial----->

${x}^{2} - (sum \: of \: zeroes) x+ (product \: of \: zeroes$


${x}^{2} - ( - 9) x+ ( - \frac{1}{9} ) = 0 \\ \\ { {x}^{2} + 9x - \frac{1}{9} } = 0 \\ \\ {9x}^{2} + 81x - 1 = 0$


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#Hope its help

Answer 2

Step-by-step explanation:

α = -9   β = -1/9

quadratic polynomial

= k {x ²- (α + β)x + αβ}

= k { x² - (-9 - 1/9)x -9 x -1/9}

= k { x² - (-19/9)x + 1}

= k { x² + 19/9 x + 1}

when k = 1

the quadratic polynomial is x² + 19/9 x + 1

Hope it helps!!

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