Question

'
Find a quadratic polynomial whose zeroes are -12 and 4 and verify the relationship between the
zeroes and the coefficients.​

Answer 1

Step-by-step explanation:

required Q.E is [x-(-12)] [x-4] = 0

= x^2-4x+12x-48 = 0

= x^2+8x-48 =0

alpha +beta =-b/a= -8 = -12+4 = -8

alphabeeta = c/a =-48 = -12×4=-48