Question

Find a quadratic polynomial whose zeroes are 2 and minus 3

Answer 1

Answer:

=x^2-x-6

Step-by-step explanation:

=sum of zeroes=alpha+beta

=2+(-3)=-1

=product of zeroes=alpha×beta

=2×(-3)=-6

Quadratic equation=x^2+Sx+P=0

x^2+(-1)x+(-6)

=x^2-x-6

Hope i had helped you

Answer 2

$x^2 + x - 6 = 0$ is the quadratic polynomial whose zeroes are 2 and minus 3

Solution:

The general form of quadratic equation is:

$x^2 -( \text{ sum of zeros })x + \text{product of zeros} = 0$

quadratic polynomial whose zeroes are 2 and minus 3

Zeros = 2 and -3

Sum of zeros = 2 -3 = -1

Product of zeros = 2 x - 3 = -6

Substituting we get,

$x^2 - (-1)x - 6 = 0 \\\\x^2 + x - 6 = 0$

Thus the quadratic polynomial is found

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