Question

Find a quadratic polynomial whose zeroes are 3 and 7.​

Answer 1

Answer:

x^2 - 10x + 21

Hope it helps you.

Thanks

Answer 2

$Let \: \alpha \:and \: \beta \: are \: zeroes \:of$

$a \: polynomial$

$\alpha = 3\: and \: \beta = 7 \: ( given )$

$\red{ The \: Quadratic \: Polynomial }$

$=k[ x^{2} - ( \alpha + \beta )x + \alpha \beta ]$

$= k [ x^{2} - ( 3 + 7 )x + 3 \times 7 ]$

$= k( x^{2} - 10x + 21)$

$If \: k = 1 , then \: the \: quadratic \: polynomial$

$is \: x^{2} - 10x + 21$

Therefore.,

$\red { Required \: polynomial : }$

$\green { = x^{2} - 10x + 21}$

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