find a quadratic polynomial whose zeroes are 7+2root2 and 7-2root2
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Answered by
3
x^2-{(7+2root2)+(7-2root2)}+(7+2root2)(7-2root2)=0
sona271:
sorry i didnt understand any thing
Answered by
5
Hello !
α = 7 + 2√2
β =7 - 2√2
α + β = sum of zeros = 7 + 2√2 + 7 - 2√2
= 14
αβ = product of zeros = (7 + 2√2)× (7 - 2√2)
= 7² - [2√2]²
= 49 - 8
= 41
quadratic polynomial :-
x² - (α + β)x + (αβ)
= x² - 14x + 41
α = 7 + 2√2
β =7 - 2√2
α + β = sum of zeros = 7 + 2√2 + 7 - 2√2
= 14
αβ = product of zeros = (7 + 2√2)× (7 - 2√2)
= 7² - [2√2]²
= 49 - 8
= 41
quadratic polynomial :-
x² - (α + β)x + (αβ)
= x² - 14x + 41
thanku
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