Question

find a quadratic polynomial whose zeroes are-7 and 3​

Answer 1

Step-by-step explanation:

alpha +beta=-b/a

-7+3= -b/a

-10= -b/a

10=b/a

alpha×beta=c/a

-7×3=c/a

-21= c/a

so, the quadric equation is x2+10-21

Answer 2

Step-by-step explanation:

Sum of zeroes=-7+3=(-4)

Products of zeroes=-7×+3=(-21)

so the quadratic equation is

$x ^{2} + 4x - 21$