Math, asked by Anonymous, 1 year ago

find a quadratic polynomial whose zeroes are in given attachment

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Answered by 9552688731
2
let this zeroes as,

m = -2/√3 and. n = √3/4
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the normal form of quadratic equation is

x²-(m+n)x+(m×n) = 0

(fill the value " m+n " and " mn " )

x²-(-2/√3 + √3/4)x + (-2/√3 × √3/4) = 0

x²-(-8+3/4√3)x + (-1/2) = 0

x²-(-5/4√3)x -1/2 = 0

x²+5x/√3 - 1/2 = 0
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9552688731: Thank you
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