find a quadratic polynomial whose zeroes are reciprocal of zeroes of the polynomial. f(x) = ax^2+bx+c, a and c is not equal to zero
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Answer:
(x+1)^2 could be the answer of your question.
Step-by-step explanation:
I'm not quite sure about your question what you meant.
But I think this could be your answer.
According to the question, we have to find a quadratic polynomial whose zeroes are the reciprocal of zeroes of that very polynomial.
Look for instance, only 1 is the number whose reciprocal remains the same.
so,
f(x) = x^2+2x+1
=(x+1)^2
=(x+1)(x+1)
Now,
(x+1)(x+1) = 0
x+1 = 0 0r, x+1 = 0
x = -1 or, x = -1
look the reciprocal of -1 is 1/-1 which means -1.
So this could be your answer.
You can also use this formula (x-1)^2.
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