Question

Find a quadratic polynomial whose zeroes exceed the zeroes of x2 +5x+6 by 2

Answer 1

sum of roots = - b/a = -5 /1 = -5
product of the roots = c/a = 6/1 = 6
given for next polynomial the zeros are exceed by 2
then Sum of roots (x+2)+(y+2) = -5
=> x+y = -5-4
therefore x+y = -9 or -9/1.......b/a in second polynomial..... 1 eqn
product of roots (x+2)(y+2) = 6
xy+2x+2y+4 = 6
xy+2(x+y) = 6-4
xy+2(-9) = 2
xy=2+18
xy=20 or 20/1.... c/a in second polynomial .... 2 eqn
so, from 1,2 eqns
a=1, b=9, c=20
∴ required polynomial is x^2+9x+20=0

Answer 2

Answer:

The solution is in the pic above...

Step-by-step explanation:

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