Question

Pls tell me how to solve this exponent sum

Answer 1

[-3(a^3/4) (b^-1/4]^4

(abc)^n = (a^n)*(b^n)*(c^n)

The above equation can be written as:

(-3^4) * [(a^3/4)^4] * [(b^-1/4)^4]
= 81 * a^(3*4/4) * b^(-1*4/4)
= 81 * a^3 * b^-1
= 81(a^3)/b           ( X^-1 = 1/X)
and your equation is solved.

Thankyou.
Hope it helps.. :)