Find a Quadratic polynomial whose zeros are 0 and 1
Answers
Answered by
37
Hiii friend,
Let Alpha = 0 and Beta = 1
Sum of zeroes = (Alpha + Beta) = (0+1) = 1
And,
Product of zeroes =(Alpha × Beta) = 0 × 1 = 0
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(1)X + 0
=> X²-X
HOPE IT WILL HELP YOU.... :-)
Let Alpha = 0 and Beta = 1
Sum of zeroes = (Alpha + Beta) = (0+1) = 1
And,
Product of zeroes =(Alpha × Beta) = 0 × 1 = 0
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(1)X + 0
=> X²-X
HOPE IT WILL HELP YOU.... :-)
Answered by
17
Hii Mate here is your Answer,
It is given that,
![\alpha = 0 \: \: and \: \: \beta = 1 \alpha = 0 \: \: and \: \: \beta = 1](https://tex.z-dn.net/?f=+%5Calpha++%3D+0+%5C%3A++%5C%3A+and+%5C%3A++%5C%3A+++%5Cbeta++%3D+1)
There is an Formula for framing a quadratic polynomial if its zeros are given...
That Formula is
![k( \: {x}^{2} - ( \alpha + \beta )x + \alpha \beta ) k( \: {x}^{2} - ( \alpha + \beta )x + \alpha \beta )](https://tex.z-dn.net/?f=k%28+%5C%3A+%7Bx%7D%5E%7B2%7D++-+%28+%5Calpha++%2B++%5Cbeta+%29x+%2B++%5Calpha++%5Cbeta+%29)
So, we have to only insert given values that is
k[x^2- (0+1) + 0×1]
= k [ x^2 -x + 0]
= x^2 -x
Here k = 1
K is a constant.
Hope this helps you a lot...☺♤♢♧☆☆☆☆☆
It is given that,
There is an Formula for framing a quadratic polynomial if its zeros are given...
That Formula is
So, we have to only insert given values that is
k[x^2- (0+1) + 0×1]
= k [ x^2 -x + 0]
= x^2 -x
Here k = 1
K is a constant.
Hope this helps you a lot...☺♤♢♧☆☆☆☆☆
Similar questions