Question

Find a quadratic polynomial whose zeros are -2√3 and √3​

Answer 1

Answer:

fdfb. vddghn. xfghh hgfdcv. ccghj

Answer 2

Step-by-step explanation:

$let \: \alpha = - 2 \sqrt{3} and \: \beta = \sqrt{3} \\ sum \: of \: zeros \: = (\alpha + \beta ) = ( - 2 \sqrt{3} + \sqrt{3} ) = - \sqrt{6} \\ \\ product \: of \: zeros \: = \alpha \beta = ( - 2 \sqrt{3} \times \sqrt{3} ) = - 6$

So, the required polynomial is

${x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = {x}^{2} - ( - \sqrt{6} )x + ( - 6) \\ = {x}^{2} + \sqrt{6} - 6$