Find a quadratic polynomial whose zeros are (√3+2
) and (√3-2
). ma
Answers
Answered by
0
Here is your answer:
Given zeros of polynomial are 3±
2
Let α,β be zeros of polynomial
then
α+β=3+
2
+3−
2
=6 ________ (1)
& αβ(3+
2
)(3−
2
)
αβ=9−3
2
+3
2
−2=7 _________ (2)
then
quadratic equation is
x
2
−(α+β)x+αβ=0
From (1) & (2)
[x
2
−6x+7=0]
Step-by-step explanation:
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