Question

Find a quadratic polynomial whose zeros are -3 and 2.​

Answer 1

hope it hlps u ..........

Answer 2

Answer:-

${x}^{2} + x - 6$

Given:-

$\alpha = - 3$

$\beta = 2$

To find :-

The required quadratic polynomial.

Solution:-

Let $\alpha ,\beta$ be the quadratic zeroes of required quadratic polynomial.

Then,

$\alpha + \beta = - 3 + 2$

$\alpha + \beta = - 1$

Also,

$\alpha \beta = ( -3 ) \times 2$

$\alpha \beta = - 6$

Required polynomial is given by :-

$\boxed{\sf{ {x}^{2} - ( \alpha + \beta )x + \alpha \beta }}$

Put the value,

→

${x}^{2} - ( - 1)x + ( - 6)$

${x}^{2} + x - 6$

hence, the required quadratic polynomial is ${x}^{2} + x - 6$