find a quadratic polynomial whose zeros are 3 and 7 respectively
Answers
Answered by
0
Answer:
3 , 6 , 9 , 12
7 , 14 , 21 , 28
it correct answer
Answered by
1
Answer:x^2-10x+21
Step-by-step explanation:x^2-10x+21
(x^2-7x)(-3x+21)
x(x-7)-3(x-7)
=(x-3). (x-7)
zeros
x=3x=7
hence, the equation required is x^2-10x+21
Similar questions