Find a quadratic polynomial with 1 zero 3-root 2 and sum of zeroes 6
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Step-by-step explanation:
Hi,
One zero = 3 - √2
Sum of zeroes = 6
One zero + Other zero = 6
3 - √2 + Other zero = 6
Other zero = 6 - ( 3 - √2 )
Other zero = 6 - 3 + √2
Other zero = 3 + √2.
Therefore,
Product of zeroes = ( 3 + √2 ) ( 3 - √2 )
=> (3)² - ( √2)²
=> 9 - 2
=> 7
Product of zeroes = 7
Therefore,
Required polynomial = x² - (sum of zeroes )x + Product of zeroes
=> X² - ( 6 )x + 7
=> x² - 6x + 7 .
Hope it will help you :)
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