find a quadratic polynomial with the given number as sum and product of its zeroes respectively (√2,1/3)
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It's very easy the polynomial is k(x^2 - (√2)x+1/3)
AyushBaghel:
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The polynomial is
k[x² - (sum of factors)x + product of factors], where k is any real number.
So, the polynomial becomes
x²-√2x+1/3
= 3x²-3√2x +1. ( Multiplying by 3).
Hope it helps.
k[x² - (sum of factors)x + product of factors], where k is any real number.
So, the polynomial becomes
x²-√2x+1/3
= 3x²-3√2x +1. ( Multiplying by 3).
Hope it helps.
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