Find a quadratic polynomial with zeros at x = 1/4 and x = –1.
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Let a and b be the zeros of p(x)
Using the relationship between zeros and coefficients,
we have p(x) = x^2 - (a +b)x+ ab
=x^2-(1/4-1)x-1/4
=x^2+(3/4)x-(1/4)
It is a polynomial with zeros 1/4 and –1.
Using the relationship between zeros and coefficients,
we have p(x) = x^2 - (a +b)x+ ab
=x^2-(1/4-1)x-1/4
=x^2+(3/4)x-(1/4)
It is a polynomial with zeros 1/4 and –1.
Anonymous:
thanks
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