find a quadratic polynomials whose sum and product of zeros 3 ,1/3
Answers
Answered by
4
HEY FRIEND
HERE IS YOUR ANSWER
GIVEN:
_____
SUM OF ZEROES =3
PRODUCT OF ZEROES =1/3
==============================
THERE ARE TWO METHODS TO SOLVE THIS :
==============================
1) FIRST METHOD :
REQUIRED POLYNOMIAL :
=x²-(sum of zeroes)x+(product of zeroes)
=x²-3x+(1/3)
=3x²-9x+1
So, the required polynomial is 3x²-9x+1.
==============================
2)SECOND METHOD:
Sum of zeroes = -b/a
3= -b/a-------(i)
Product of zeroes =c/a
1/3=c/a
TO MAKE THE VALUE OF (a) EQUAL
Multiply and divide 3 by3
in equation 1
We will get
-b/a=9/3
From this we get
a=3
b= -9
c=1
Put it in ax²+bx+c
3x²-9x+1
So the required polynomial is 3x²-9x+1
=============================
HOPE THIS HELPS YOU
HERE IS YOUR ANSWER
GIVEN:
_____
SUM OF ZEROES =3
PRODUCT OF ZEROES =1/3
==============================
THERE ARE TWO METHODS TO SOLVE THIS :
==============================
1) FIRST METHOD :
REQUIRED POLYNOMIAL :
=x²-(sum of zeroes)x+(product of zeroes)
=x²-3x+(1/3)
=3x²-9x+1
So, the required polynomial is 3x²-9x+1.
==============================
2)SECOND METHOD:
Sum of zeroes = -b/a
3= -b/a-------(i)
Product of zeroes =c/a
1/3=c/a
TO MAKE THE VALUE OF (a) EQUAL
Multiply and divide 3 by3
in equation 1
We will get
-b/a=9/3
From this we get
a=3
b= -9
c=1
Put it in ax²+bx+c
3x²-9x+1
So the required polynomial is 3x²-9x+1
=============================
HOPE THIS HELPS YOU
Answered by
1
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____________________________
★★★THE END★★★
it is ypur answer.......
I think it will help you then you mark me brainlist please please please. .......
♣♣♣♣♣♣♣♣♣♣♣♣♣♣♣♣
____________________________
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