Question

find a Quadratic whose zeres are
1 and-3Verify the relashion ship btw
Coefficients & zeroes of polynomial​

Answer 1

Answer:

x²+2x-3

Step-by-step explanation:

Given zeroes are 1 & - 3

Therefore assuming alpha as 1 and beeta as - 3

Therefore sum of zeroes of polynomial = - b/a

1+(-3) = - b/a

-2 = - b/a (- gets cancelled being same signs)

2 = b/a

Product of zeroes of polynomial = c/a

1*(-3) = c/a

-3 = c/a

Therefore the values are a = 1, B = 2 and c = - 3

So by substituting the values in the standard form ax²+bx+c=0

x²+2x-3 = 0