Question

find a quadritic polynomial with zeroes 3+ root 2 and 3-root 2

Answer 1

sum of roots = 3 + √2 + 3 - √2 = 6
product of roots = (3+√2)(3-√2) = 9-2 = 7


so quadratic eqn = x² - x(sum of roots) + product of roots
           ⇒ x² - 6x +7 = 0

Answer 2

Hello there !!


Zeroes = 3 + √2 , 3 - √2

Sum of zeroes = 3 + √2 + 3 - √2 = 6

product of zeroes = (3+√2) x (3-√2) =3² - [√2]²
= 9 - 2 = 7


quadratic eqquation = x² - (sum of roots)x + product of roots
---) x² - 6x +7 = 0


Hope this Helped You !!