Question

find a recursive formula for the general term: 2, 3, 6, 18, 108, 1944​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

Answer:

e(1) = 2,   e(n+1) = e(n-1)*e(n)  for n > 1

f(1) = 1,   f(n) = n*f(n-1)  for n > 1

Step-by-step explanation:

Given sequences

e) 2, 3, 6, 18, 108, 1944, ...

f) 1, 2, 6, 24, ...

To find

Recursive formula for the general term

Solution

We can observe that

e) 2*3 = 6, 3*6= 18, 18*6= 108, 108*18 = 1944

f) 1*2 = 2, 2*3= 6, 6*4= 24

We can put it in general terms as

e(1) = 2,  and e(n+1) = e(n)*e(n-1)  for n > 1

f(1) = 1,  and f(n) = f(n-1)*n  for n > 1

Answer 2

Answer:

find a recursive formula for the general term: 2, 3, 6, 18, 108, 1944