Question

Find a relation between x and y such that point p(x,y) is equidistant from the points a(-5,3) and b(7,2)

Answer 1

Given that
 ap=bp
$\sqrt{ (3-y)^{2}+ (-5-x)^{2}} = \sqrt{ (7-x)^{2} + (2-y)^{2} }$
By Squaring both the sides,
[tex] (-5-x)^{2} + (3-y)^{2}= (7-x)^{2}+ (2-y)^{2} [/tex]
25+$x^{2}$+10x+9+$y^{2}$-6y=49+$x^{2}$-14x+4+$y^{2}$-4y
24x=19+2y
24x-2y=19
This the relation between x and y for the given condition

Answer 2

Answer:

Hope it helps.