Find a relation between x and y such that the point (x, y) is equidistant from the point
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we have to find the relation between x and y such that the point (x, y) is the equidistant from the points (3, 6) and (-3,4). solution : using distance formula, let P = (x, y) , Q = (3, 6) and R = (-3, 4). Therefore the relation between x and y is 3x + y = 5.
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