Question

Find a relation between x and y such that the point (x, y) is equidistant from the point
(3,6) and (-3,4).​

Answer 1

Step-by-step explanation:

Dostace from both pts to x,y is same

√(x-3)^2 + (y-6)^2 = √(x- -3)^2 + (y-4)^2

(x-3)^2 + (y-6)^2 = (x+3)^2 = (y-4)^2

Solve the equation for the relation