Question

Find a relation between x and y such that the point (x , y) is equidistant from the points (7, 1) and (3, 5)

Answer 1

A(7,1)      and    B(3,5)

Point C(x, y).
  CA = CB
  CA² = CB²
       (x - 7)² + (y - 1)² = (x - 3)² + (y - 5)²
        x² + y² - 14 x + 49 -2 y + 1 = x² - 6 x + 9 + y² - 10 y + 25
         8 x = 8 y + 24

             y = x - 3

Answer 2

Answer:

Step-by-step explanation:

A(7,1)      and    B(3,5)

Point C(x, y).

 CA = CB

 CA² = CB²

      (x - 7)² + (y - 1)² = (x - 3)² + (y - 5)²

       x² + y² - 14 x + 49 -2 y + 1 = x² - 6 x + 9 + y² - 10 y + 25

        8 x = 8 y + 24

            y = x - 3