Find a relation between x and y such that the point (x, y) is equidistant from the points (-2, 4) and (3,5).
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A(x, y) is equidistant from the points B(-2, 4) and C (3,5).
AB^2=BC^2
(x+2)^2+(y-4)^2=(x-3)^2+(y-5)^2
x^2 +4+ 4x +y^2+16 - 8y=x^2+9 -6x +y^2 +25 -10y
20+ 4x -8y=34 -6x -10y
10x=14-2y
10x+2y=14
5x+y=7
Step-by-step explanation:
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