Question

find a relation between x and y such that the point x,y is equidistant from the point 3,6 and -3,4.​

Answer 1

$=> \sqrt{ {(x - 3)}^{2} + {(y - 6)}^{2} } = \sqrt{ {(x + 3)}^{2} + {(y - 4)}^{2} } \\ \\=> {(x - 3)}^{2} + {(y - 6)}^{2} = {(x + 3)}^{2} + {(y - 4)}^{2} \\ \\ =>{x}^{2}+9-6x+{y}^{2}-12y+36={x}^{2}+6x+9+{y}^{2}-8y+16 \\ \\ => - 12x - 4y = - 20 \\ \\ = > 3x - y = 5$