Question

in the figure angle GCE=angle CEG prove that angle ACG =angle BEG, urgent plss answer ​

Answer 1

Step-by-step explanation:

Given,

BC=EF

Since ABCD is a square, sides are equal

AF=AB

∠B=∠F

Therefore from SAS theorem

ABC≅AFE

⟹AC=AE Hence the triangle is isoceles.

AEG≅ACG

Therefore from ASA theorem

ACG≅AEG

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