Question

find a relation between x and Y such that the point ( x , y ) is equidistant from the point ( 6, 1 ) and ( 3 , 5 )​

Answer 1

Answer:

According to statement

$\sqrt{ {(x - 6)}^{2} + {(y - 1)}^{2} } = \sqrt{ {(x - 3)}^{2} + {(y - 5)}^{2} } \\ squaring \: both \: sides \\ {x}^{2} + 36 - 12x + {y}^{2} + 1 - 2y = {x}^{2} + 9 - 6x + {y}^{2} + 25 - 10y \\ 37 - 12x - 2y = 34 - 6x - 10y \\ 6x - 8y = 3$