Find a relation between x and y such that the point (x, y) is equidistant
from the points (7, 1) and (-3,-5).
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Step-by-step explanation:
using distance formula,
√[(7 - x)² + (1 - y)²] = √[(-3 - x)² + (-5 - y)²]
=> taking square root on both sides
=> 49 + x² - 14x + 1 + y² - 2y = 9 + x² + 6x + 25 + y² + 10y
=> x² + y² - 14x - 2y + 50 = x² + y² + 6x + 10y + 34
=> -14x - 2y + 50 = 6x + 10y + 34
=> -14x - 6x - 2y - 10y = 34 - 50
=> -20x - 12y = - 16
=> 5x - 3y = 4
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