Question

Find a relation between x and y such that the point (x,y) is equidistant from the points (7,1) and(3,5).

Answer 1

let P(x, y) be equidistant from the point A(7, 1) and B(3, 5)
PA=PB
squaring on both sides
PA^2=PB^2
(x-7) ^2+(y-1) ^2=(x-3) ^2+(y-5) ^2
x^2-14x+7^2+y^2-2y+1^2=x^2-6x+3^2+y^2-10y+5^2
-14x+49-2y+1=-6x+9-10y+25
-14x+6x-2y+10y+50=34
-8x+8x=34-50
-8x+8y=-16
divide both side by -8
x-y=2
the required relation between x and y is x-y=2




hope it will help u