Question

Find a relation between x and y such that the point (x , y) is equidistant from the points (7, 1) and (3, 5).

Answer 1

equidistant = midpoint of the two coordinates

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Midpoint of (7, 1) and (3, 5):

$= \big (\dfrac{7+ 3}{2} , \dfrac{1 + 5}{2} \bigg)$

$= (5 , 3 )$

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Answer: (x , y) = (5. 3)