Question

find a root of an equation f(x)=x^3-x^2+x-7 between 2 and 3,using False position method.​

Answer 1

Answer:

$x {}^{3} - x {}^{2} + x - 7$

put the value of 2

$(2) {}^{3} - (2) {}^{2} + 2 - 7 \\ 8 - 4 + 2 - 7 \\ 4 + 2 - 7 \\ 6 - 7 = - 1$

put the value of 3

(3) ^3 - (3) ^2+ 3 - 7

27 - 9+ 3 - 7

18+3-7

21-7

14

Answer 2

Answer:

14 is the answer here

thank you