Math, asked by naitikarora, 9 months ago

find a sequence of 5 consecutive numbers none of which are prime

Answers

Answered by sreesrh2008
3

Answer:

Using the Chinese Remainder Theorem you can find X such that each of

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,X−2≡0mod52,

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,X−2≡0mod52,X−3≡0mod72,

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,X−2≡0mod52,X−3≡0mod72,X−4≡0mod112

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,X−2≡0mod52,X−3≡0mod72,X−4≡0mod112holds.

Using the Chinese Remainder Theorem you can find X such that each ofX≡0mod22,X−1≡0mod32,X−2≡0mod52,X−3≡0mod72,X−4≡0mod112holds.Of course this can be generalized for any desired number of consecutive non-squarfree numbers.

Answered by vitthalshinde41
8

24,25,26,27,28,29

i hope it is correct answer

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