Math, asked by brainlymember14, 1 day ago

Find a set of four consecutive positive integers such that the smallest is a multiple of 5, the second is a multiple of 7, the third is a multiple of 9, and the largest is a multiple of 11.

Answers

Answered by shakshijain
1

Answer:

1735, 1736, 1737, 1738 are the 4 consecutive positive integers dividing 5,7,9&11 respectively.

Similar questions