Math, asked by sarithabathulla, 10 months ago

find a smallest four digit number which is divisible by 18,24 and 32​

Answers

Answered by gourirupa
2

Answer:- 1152

First we find the LCM of 18,24,32

18 = 2 * 3²

24 = 2³ * 3

32 = 2^5

So LCM = 2^5 * 3^2 = 32*9 = 288

Smallest 4-digit no. = 1000

After this, check the attachment and notice that the remainder is 136 .

So the number that is divisible by 288 = (1000 - 136) = 864.

But 864 is not a 4-digit number .

So to make it a 4-digit number and keeping it divisible by 288, we do (864 + 288) = 1152.

Hence 1152 is the smallest 4-digit number divisible by 18,24,32 .

Hope this helps you .

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Answered by varunsai33k
0

Answer:

find the LCM for 3 numbers,

2\18,24,32

=\9,12,16

=2×9×12×16

= 3456.

Step-by-step explanation:

hope it helps....

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