Question

find a solution of the pair of equations x/10+y/5 =1 and x/8+y/6=15.hence find k if y=kx+5.

Answer 1

take L.C.M. for both equations you get
(x+2y)/10=1---(i)
=> x+2y=10( by cross multiplication)
(3x+4y)/24=15
=>3x+4y=360-----(ii)
multiply (i) with 2
subtract (i) from (ii)
3x+4y=360
-2x-4y=-20
you get the  answer x=340
substitue this in (i)
340+2y=10
2y= -330
y= -330/2
= -165
y=kx+5
substitue x and y
-165=340k+5
340k = -170
k= -170/340
=-1/2
= - 0.5

Answer 2

Step-by-step explanation:

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