Question

find a solution
plz .. ​

Answer 1

$x = 3 - 2 \sqrt{2} \\ \frac{1}{x} = \frac{1}{3 - 2 \sqrt{2} } \\ \frac{1}{x} = \frac{3 + 2 \sqrt{2} }{9 - 8} \\ \frac{1}{x} = 3 + 2 \sqrt{2} \\ \\ x + \frac{1}{x} = 6 \\ x + \frac{1}{x} + 2 = 8 \\ ( { \sqrt{x} + \frac{1}{ \sqrt{x} } })^{2} = 8 \\ \sqrt{x} + \frac{1}{ \sqrt{x} } =± 2 \sqrt{2}$