Question

find a suitable identity and find the following products (3k+4l) (3k+4l)
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Answer 1

Answer:

3k+4 ×3k+4

Step-by-step explanation:

do the multiplication of them

Answer 2

$\large\sf\underline{Given\::}$

• $\sf\:(3k+4l) (3k+4l)$

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$\large\sf\underline{To\::}$

• Find the product of the given expression by using some identity.

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$\large\sf\underline{Identity\:to\:be\:used\::}$

✧ $\large{\mathfrak\red{(a+b)^{2}=a^{2}+2ab+b^{2}}}$

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$\large\sf\underline{Solution\::}$

‎ $\sf\leadsto\:(3k+4l) (3k+4l)$

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• Let's express our expression in the form of $\sf\:(a+b) ^{2}$ .

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$\sf\leadsto\:(3k+4l) ^{2}$

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• Now we can simply use the identity

In our expression a = 3k and b = 4l

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• So let's substitute the values accordingly in the identity

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$\sf\leadsto\:(3k) ^{2}+2 \times 3k \times 4l + (4l)^{2}$

$\sf\leadsto\:9k^{2}+6k \times 4l + 16l^{2}$

$\small{\underline{\boxed{\mathrm\orange{\leadsto\:9k^{2}+24kl + 16l^{2}}}}}$ ★

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‎ $\dag\:\underline{\sf So\:the\:required\:product\:is\:9k^{2}+24kl + 16l^{2}}$ .

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!! Hope it helps !!