Question

Q1.A body of mass 6 kg accelerates from 6 m/s to 18 m/s in 3 seconds due to the application of a force on it. Calculate the magnitude of this force (in N)

Answer 1

Step-by-step explanation:

Answer:

The required force is 24 N

Step-by-step explanation:

Given :

A body of mass 6 kg accelerates from 6 m/s to 18 m/s in 3 seconds due to the application of a force on it.

To find :

the magnitude of the force

Solution :

First, let's find the acceleration of the given object.

We know, acceleration is the rate of change of velocity.

$\boxed{\sf a = \dfrac{v-u}{t}} </p><p>$

where

v denotes the final velocity

u denotes the initial velocity

t denotes the time taken

______________________

Given,

u = 6 m/s

v = 18 m/s

t = 3 s

So, acceleration, a = (18 - 6)/3

a = 12/3

a = 4 m/s²

Therefore, the acceleration is 4 m/s²

______________________

We know,

⟼F=ma

where

m denotes the mass of the body

a denotes it's acceleration.

=> F = 6 kg × 4 m/s²

=> F = 24 kg m/s²

=> F = 24 N

Answer 2

Answer:

answer is 24N force is acting on the body

Step-by-step explanation:

first find acceleration:-

u = 6m/s

t = 3s

v = 18m/s

a = u-v/t

= 18 - 6 / 3 = 12/3 = 4m/s

therefore, Force = mass×acceleration

F = 6 × 4

F = 24N