Find (a) the total number and (b) the total mass of neutrons in 7 mg of 14 C.
( Assume that mass of a neutron = 1.675 x 10^27 kg . )
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Answered by
5
Answer:
The number of neutrons is equal to the difference in the mass number and atomic number.
It is equal to 14−6=8.
(a) The number of neutrons present in 7 mg of C-14:
=
14
7×10
−3
×6.02×10
23
×8
=2.408×10
21
neutrons
(b) Total mass of neutrons in 7 mg of C-14:
=2.4088×10
21
×1.675×10
−27
=4.035×10
−6
kg.
Answered by
4
Answer:
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Explanation:
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