Chemistry, asked by patilruchita, 20 days ago

Find (a) the total number and (b) the total mass of neutrons in 7 mg of 14 C.
( Assume that mass of a neutron = 1.675 x 10^27 kg . )​

Answers

Answered by harbhajanpatwar1980
5

Answer:

The number of neutrons is equal to the difference in the mass number and atomic number.

It is equal to 14−6=8.

(a) The number of neutrons present in 7 mg of C-14:

=

14

7×10

−3

×6.02×10

23

×8

=2.408×10

21

neutrons

(b) Total mass of neutrons in 7 mg of C-14:

=2.4088×10

21

×1.675×10

−27

=4.035×10

−6

kg.

Answered by dhanshreetate45
4

Answer:

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Explanation:

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