Question

find a unit vector parallel to A is given by a=2l^+4j^+k^

Answer 1

Answer:

there can be unit vectors parallel A one which is  2i^+4j^+k^/$\sqrt{21}$

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Explanation:

any vector parallel to a is of the form λ(2i^+4j^+k^)

where λ is any rational number.

let me take λ=2

so the vector parallel to a is 4i^+8j^+2k^(let this vector be b)

unit vector of a vector can be obtained by dividing the vector by its magnitude.

magnitude of vector b is $\sqrt{ 4^{2}+ 8^{2}+ 2^{2} } =\sqrt{84} =2\sqrt{21}$

so the required unit vector is 4i^+8j^+2k^/$2\sqrt{21}$ = 2i^+4j^+k^/$\sqrt{21}$