Question

Find a value of A when cos 2A = sin3A​

Answer 1

Answer:

Sin(90-2a) =sin3a

=. 90-2a=3a

=. 3a+2a=90

=. 5a=90

=. A=90/5

=. A.=18

Step-by-step explanation:

Pls Mark as brainest answer and follow me pls

Answer 2

Answer:

Sin(90-2a)= sin 3a

=.90-2a=3a

=.3a+2a=60

=.5a=90

=.A=90/5

=.A.=18

Step-by-step explanation:

This is my answer

Koi problem ho to plz comment kariye