Find a vector perpendicular to both the vectors i-2j+3k and i+2j-k
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Answer:
(-i+j+k)/√(3)
Step-by-step explanation:
Let A=ai+bj+ck be a vector which is perpendicular to B=i-2j+3k and C=i+2j-k.
A.B=0 and A.C=0=>
a-2b+3c=0
a+2b-c=0
=> a/(2-6)=b/(3+1)=c/(2+2)
=>a/(-1)=b/1=c/1
Thus A=-i+j+k.
Hence required unit vector along vector A=(-i+j+k)/√(3).
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