Question

find a where ab/ac =1/2 and b(3,2) and c(6,11) in cartesian plane​

Answer 1

Answer:

C(9,8,−10) are collinear, find the ratio in which B divides

AC

.

Medium

share

Share

Answer

Given that

Point A(3,2,-4), B(5,4,-6) & C(9,8,-10) are collinear

B must divide line segment AC in some ratio externally and internally

We know that

Co-ordinate of point A(x,y,z) that divides line segment joining (x

1

,y

1

,z

1

) and (x

2

,y

2

,z

2

) in ratio m:n is

(x,y,z)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Let point B(5,4,−6) divide line segment A(3,2,−4) and C(9,8,−10) in the ratio k:1

B(5,4,−6)=(

k+1

9k+3

,

k+1

8k+2

,

k+1

−10k−4

)

Comparing x-coordinate of B

5=

k+1

9k+3

5k+5=9k+3

9k−5k=5−3

4k=2

k=

2

1

So, k:1=1:2

Thus, point B divides AC in the ratio 1:2

Answer 2

$\huge\fcolorbox{red}{lightgreen}{Answer}$

Refer to the attachment

Step-by-step explanation:

$\fcolorbox{red}{aqua}{♡@ItzSongLover♡}$